document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=817212>Question 817212</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If one side of a square is increased by 4 inches and an adjacent side is multiplied by 4,the perimeter of the resulting rectangle is 3 times the perimeter of the square. find the side of the original square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #491944 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=491944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The original side of the square = x<BR>\n" );
document.write( "One side becomes x + 4<BR>\n" );
document.write( "Adjacent side = 4x<BR>\n" );
document.write( "Perimeter of rectangle = 3* perimeter of square<BR>\n" );
document.write( "2(x + 4) +2(4x) = 3* 4x<BR>\n" );
document.write( "2x + 8 + 8x = 12x<BR>\n" );
document.write( "10x - 12x = -8<BR>\n" );
document.write( "-2x = -8<BR>\n" );
document.write( "Multiply both sides by -1<BR>\n" );
document.write( "2x = 8<BR>\n" );
document.write( "x = 4 inches<BR>\n" );
document.write( "Original side of square = 4 inches.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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