document.write( "Question 817157: [ A train leaves San Diego at 3:00 pm. A second train leaves the same city traveling in the same direction at 6:00 pm. The second train travels 45 mph faster than the first. If the second train overtakes the first at 10:00 pm, what is the speed of each of the two trains. ] \n" ); document.write( "
Algebra.Com's Answer #491904 by mathgranny(13)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " Train 1. d = rt. Train 2 d = rt\r
\n" ); document.write( "\n" ); document.write( " r1 means rate of train 1, r2 means rate of train 2\r
\n" ); document.write( "\n" ); document.write( " Rate of train 2 is 45 mph faster than train 1
\n" ); document.write( " r2 = r1 + 45\r
\n" ); document.write( "\n" ); document.write( " Time for train 1 to reach same spot at 10:00 is t1 = 7 hrs.
\n" ); document.write( " Time for train 2 to reach same spot at 10:00 is t2 = 4 hrs.\r
\n" ); document.write( "\n" ); document.write( " distance coverd by 10:00 is the same
\n" ); document.write( " d1 =. d2\r
\n" ); document.write( "\n" ); document.write( " d1 = rt = (r1)(7). d2 = ( r2)t = (r1 + 45) 4
\n" ); document.write( " So 7(r1) = (r1 + 45) 4
\n" ); document.write( " 7(r1) = 4(r1)+ 180
\n" ); document.write( " Solve for r1 to get r1 = 60 mph
\n" ); document.write( " Train 2 is 45 mph faster so rate of train 2 is 105 mph
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