document.write( "Question 69112: how many liters of a 10% acid solution must be mixed with a 50% acid solution in order to obtain 20 liters of a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #49188 by checkley75(3666)\"\" \"About 
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.1(20-x)+.5x=.2*20
\n" ); document.write( "2-.1x+.5x=4
\n" ); document.write( ".4x=2
\n" ); document.write( "x=2/.4
\n" ); document.write( "x=5 liters of 50% acid solution
\n" ); document.write( "20-5=15 liters of 10% acid solution
\n" ); document.write( "proof
\n" ); document.write( ".1*15+.5*5=4
\n" ); document.write( "1.5+2.5=4
\n" ); document.write( "4=4
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\n" ); document.write( "MY APPOLOGIES: I MISTAKENLY USED 20% OF 20 LITERS INSTEAD OF 30% OF 20 LITERS:
\n" ); document.write( "THUS THE EQUATION SHOULD HAVE BEEN
\n" ); document.write( ".1(20-X)+.5X=.3*20
\n" ); document.write( "2-.1X+.5X=6
\n" ); document.write( ".4X=6-2
\n" ); document.write( ".4X=4
\n" ); document.write( "X=4/.4
\n" ); document.write( "X=10 LITERS OF 50% IS REQUIRED TO MAKE 20 LITERS OF 30%.
\n" ); document.write( "I MUST HAVE BEEN HALF ASLEEP WHEN I DID THIS PROBLEM LAST NIGHT. AGAIN I'M SORRY FOR THE MISTAKE.
\n" ); document.write( "HOPE THIS WILL NOT DISCOURAGE YOU FROM USING ALGEBRA.COM IN THE FUTURE TO HELP WITH YOUR MATH DIFFICULTIES.
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