document.write( "Question 817058: What is are the steps to solving this quadratic formula 3/4x^2-2x+1/2=0. Thank you. \n" ); document.write( "
Algebra.Com's Answer #491856 by mananth(16946)\"\" \"About 
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(3/4)x^2-2x+(1/2)=0\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 4\r
\n" ); document.write( "\n" ); document.write( "3x^2-8x+2=0\r
\n" ); document.write( "\n" ); document.write( "solve by quadratic formula
\n" ); document.write( "a= 3 , b= -8 , c= 2
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\n" ); document.write( "b^2-4ac= 64 + -24
\n" ); document.write( "b^2-4ac= 40
\n" ); document.write( "\"%09sqrt%28%0940%09%29=%096.32%09\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 8 + 6.32 )/ 6
\n" ); document.write( "x1= 2.39
\n" ); document.write( "\"x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x2=( 8 -6.32 ) / 6
\n" ); document.write( "x2= 0.28 \r
\n" ); document.write( "\n" ); document.write( "x=2.39,Or 0.28
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