document.write( "Question 69100: sqrt(x + 4) + sqrt(x - 1) = 5 \n" ); document.write( "
Algebra.Com's Answer #49184 by ankor@dixie-net.com(22740)\"\" \"About 
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sqrt(x + 4) + sqrt(x - 1) = 5
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\n" ); document.write( "Subtract Sqrt(x-1) from both sides:
\n" ); document.write( "Sqrt(x+4) = 5 - Sqrt(x-1)
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\n" ); document.write( "Square both sides; FOIL (5-Sqrt(x-1)(5-Sqrt(x-1); results:
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\n" ); document.write( "x + 4 = 25 - 5*Sqrt(x-1) - 5*Sqrt(x-1) + (x-1)
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\n" ); document.write( "x + 4 = 25 - 10*Sqrt(x-1) + x - 1; remove the brackets
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\n" ); document.write( "x + 4 = 25 - 1 + x - 10Sqrt(x-1)
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\n" ); document.write( "x + 4 = 24 + x - 10Sqrt(x-1)
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\n" ); document.write( "x - x + 4 - 24 = -10Sqrt(x-1); get Sqrt on the right by itself
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\n" ); document.write( "-20 = -10Sqrt(x-1)
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\n" ); document.write( "Square both sides again, gets rid of the last radical and you have:
\n" ); document.write( "+400 = +100(x-1)
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\n" ); document.write( "400 = 100x - 100
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\n" ); document.write( "400 + 100 = 100x
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\n" ); document.write( "500 = 100x
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\n" ); document.write( "5 = x
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\n" ); document.write( "Check solution x = 5 in original equation:
\n" ); document.write( "sqrt(x + 4) + sqrt(x - 1) = 5
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\n" ); document.write( "sqrt(5 + 4) + sqrt(5 - 1) = 5
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\n" ); document.write( "sqrt(9) + sqrt(4) = 5
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