document.write( "Question 816906: Find the value of \"a\" for which the graph of the first equation is perpendicular to the graph of the second equation.
\n" ); document.write( "Ex:
\n" ); document.write( "y = ax - 5 ; 2y = 3x
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Algebra.Com's Answer #491772 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Find the value of \"a\" for which the graph of the first equation is
\n" ); document.write( " perpendicular to the graph of the second equation.
\n" ); document.write( "Ex:
\n" ); document.write( "y = ax - 5 ; 2y = 3x
\n" ); document.write( "Using the standard slope-intercept form for an equation of a line y = mx + b
\n" ); document.write( "where m is the slope and b the y-intercept.
\n" ); document.write( " 2y = 3x 0r \"y+=+highlight%283%2F2%29x\" m = \"3%2F2\"
\n" ); document.write( "Perpendicular lines have slopes that are negative reciprocals of one another:
\n" ); document.write( " y = ax - 5 m = \"%28-2%2F3%29\" Note: \"%283%2F2%29%28-2%2F3%29+=+-1\"
\n" ); document.write( "\"+y+=+highlight%28-2%2F3%29x+-+5\"
\n" ); document.write( " a = \"%28-2%2F3%29\"
\n" ); document.write( "graphs of \"y+=+highlight%283%2F2%29x\"(Green) and \"+y+=+highlight%28-2%2F3%29x+-+5\"(Blue)
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