document.write( "Question 816155: How to factor 2x^3-x^2-10x+5 by grouping \n" ); document.write( "
Algebra.Com's Answer #491738 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I find that factoring by grouping is easier if you
\n" ); document.write( " \n" ); document.write( "Now we group: \n" ); document.write( " \n" ); document.write( "Next we factor out the GCF from each group. The GCF of the first group is \n" ); document.write( " \n" ); document.write( "As we can see the \"non-GCF\" factors, (2x+(-1)) and (-2x+1) are not the same. So it appears that factoring by grouping is not working for us. But these two factors are exact opposites of each other. This is when factoring our the negative of the GCF can be very helpful. Instead of factoring 5 out of the second group of \n" ); document.write( " \n" ); document.write( "Now the \"non-GCF\" factors are the same and we can proceed. Next we factor out the GCF of the two groups, (2x+(-1)): \n" ); document.write( " \n" ); document.write( "Since neither of these factors will factor further, we are finished factoring. At this point additions of negatives may be changed back to subtractions if you prefer. So the answer is either \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( " |