document.write( "Question 816844: How many liters each of 25% and 60% alcohol solutions must be mixed together to make 40 liters of a 53% alcohol solution?
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Algebra.Com's Answer #491735 by TimothyLamb(4379) $\"\"$ $\"About$

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w = weak solution volume
\n" ); document.write( "s = strong solution volume
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\n" ); document.write( "alcohol in the mixed solution:
\n" ); document.write( "0.25w + 0.60s = 0.53*40
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\n" ); document.write( "total volume in the mixed solution:
\n" ); document.write( "w + s = 40
\n" ); document.write( "w = 40 - s
\n" ); document.write( "---
\n" ); document.write( "0.25w + 0.60s = 0.53*40
\n" ); document.write( "0.25(40 - s) + 0.60s = 21.2
\n" ); document.write( "10 - 0.25s + 0.60s = 21.2
\n" ); document.write( "0.35s = 11.2
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\n" ); document.write( "Answer:
\n" ); document.write( "s = 32 liters
\n" ); document.write( "w = 8 liters
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