document.write( "Question 816819: x+2y=200 (first part)
\n" ); document.write( "x=y+50 (final part)
\n" ); document.write( "I need help with the steps if you could tell me the steps I would be grateful. \n" ); document.write( "
Algebra.Com's Answer #491718 by richwmiller(17219)\"\" \"About 
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x+2y=200
\n" ); document.write( "x=y+50
\n" ); document.write( "substitute y+50 for x
\n" ); document.write( "x+2y=200
\n" ); document.write( "(y+50)+2y=200
\n" ); document.write( "3y=150
\n" ); document.write( "y=50
\n" ); document.write( "x=y+50
\n" ); document.write( "x=100\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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