document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55427>Question 55427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the distance between the pair of points (-1, -4) abd (-5, -7) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49170 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the point slope formula to find the horizontal and vertical distances between the points<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 ALIGN=MIDDLE  ALT=\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >m=slope<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=%28-7-%28-4%29%29%2F%28-5-%28-1%29%29 ALIGN=MIDDLE  ALT=\"m=%28-7-%28-4%29%29%2F%28-5-%28-1%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >Plug in x and y values of the points<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=%283%29%2F%284%29 ALIGN=MIDDLE  ALT=\"m=%283%29%2F%284%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >Simplify<BR>\n" );
document.write( "Since the slope is 3/4, it really means between the points (-1, -4) and (-5, -7) the vertical distance (\"rise\") is 3 and the horizontal distance (\"run\") is 4. However, we want the diagonal distance between the points, which happens to be the hypotenuse of the vertical and horizontal lengths. So to find the hypotenuse we use Pythagoreans theorem to find it<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2Bb%5E2=c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2Bb%5E2=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >Pythagoreans theorem: in this case a and b are known lengths and c is the hypotenuse<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%5E2%2B4%5E2=c%5E2 ALIGN=MIDDLE  ALT=\"3%5E2%2B4%5E2=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >Plug in known points<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9%2B16=c%5E2 ALIGN=MIDDLE  ALT=\"9%2B16=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >Simplify   <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=25=c%5E2 ALIGN=MIDDLE  ALT=\"25=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2825%29=sqrt%28c%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%2825%29=sqrt%28c%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >isolate c by taking square root of both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=5 ALIGN=MIDDLE  ALT=\"c=5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So distance between the two points is 5 units\r<BR>\n" );
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