document.write( "Question 69085: Bob invested $20,000, part at 14% and part at 13%. If the total interest at the end of the year is $2,720, how much did he invest at 14%?\r
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document.write( "Please help me on this
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Algebra.Com's Answer #49166 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! P*R*T = I \n" ); document.write( "T = 1 \n" ); document.write( "P*R = I \n" ); document.write( "I + I = 2720 \n" ); document.write( "x*0.14 + (20,000 - x)*0.13 = 2720 \n" ); document.write( "0.14x + 2600 - 0.13x = 2720 \n" ); document.write( "0.01x = 120 \n" ); document.write( "x = $12,000 in 14% \n" ); document.write( " |