document.write( "Question 69085: Bob invested $20,000, part at 14% and part at 13%. If the total interest at the end of the year is $2,720, how much did he invest at 14%?\r
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Algebra.Com's Answer #49166 by Nate(3500)\"\" \"About 
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P*R*T = I
\n" ); document.write( "T = 1
\n" ); document.write( "P*R = I
\n" ); document.write( "I + I = 2720
\n" ); document.write( "x*0.14 + (20,000 - x)*0.13 = 2720
\n" ); document.write( "0.14x + 2600 - 0.13x = 2720
\n" ); document.write( "0.01x = 120
\n" ); document.write( "x = $12,000 in 14%
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