document.write( "Question 816657: The length of a rectangle is twice its width.
\n" ); document.write( "If the perimeter of the rectangle is 54 m , find its area \n" ); document.write( "

Algebra.Com's Answer #491649 by TimothyLamb(4379) $\"\"$ $\"About$

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L = 2w
\n" ); document.write( "p = 2L + 2w = 54
\n" ); document.write( "---
\n" ); document.write( "2L + 2w = 54
\n" ); document.write( "2(2w) + 2w = 54
\n" ); document.write( "4w + 2w = 54
\n" ); document.write( "6w = 54
\n" ); document.write( "w = 9
\n" ); document.write( "L = 2w = 18
\n" ); document.write( "---
\n" ); document.write( "a = Lw
\n" ); document.write( "a = 18 * 9
\n" ); document.write( "---
\n" ); document.write( "Answer:
\n" ); document.write( "a = 162 sq.m
\n" ); document.write( "---
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