document.write( "Question 816638: A boat takes 2/3 as much time to travel downstream as to return. If the rate of the river's current is 8 kph, what is the rate of the boat in still water? \n" ); document.write( "

Algebra.Com's Answer #491631 by TimothyLamb(4379) $\"\"$ $\"About$

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time to return: t
\n" ); document.write( "time to go: (2/3)t
\n" ); document.write( "---
\n" ); document.write( "w = 8 kph
\n" ); document.write( "---
\n" ); document.write( "s = d / t
\n" ); document.write( "d = s * t
\n" ); document.write( "D = trip distance one way
\n" ); document.write( "---
\n" ); document.write( "D = (b + w)(2/3)t
\n" ); document.write( "D = (b - w)t
\n" ); document.write( "---
\n" ); document.write( "(b + w)(2/3)t = (b - w)t
\n" ); document.write( "(b + w)(2/3) = (b - w)
\n" ); document.write( "(2/3)b + (2/3)w = b - w
\n" ); document.write( "(2/3)w + (3/3)w = (3/3)b - (2/3)b
\n" ); document.write( "(5/3)w = (1/3)b
\n" ); document.write( "b = 3(5/3)8
\n" ); document.write( "---
\n" ); document.write( "b = 40 kph
\n" ); document.write( "---
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