document.write( "Question 816617: the organizers of a charity concert sold tickets at two different prices. if they had sold 112 of the dearer tickets and 60 of the cheaper ones they would have received $45.60, but if they had sold 96 of the dearer tickets and 120 of the cheaper ones they would have received $52.80. find the price of the dearer tickets. \n" ); document.write( "
Algebra.Com's Answer #491610 by mananth(16946)\"\" \"About 
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x= cost of dearer ticket
\n" ); document.write( "y= cost of cheaper ticket
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\n" ); document.write( "112.00 x + 60.00 y = 45.60 .............1
\n" ); document.write( "Total value
\n" ); document.write( "96.00 x + 120.00 y = 52.80 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -2.00
\n" ); document.write( "Multiply (2) by 1.00
\n" ); document.write( "-224.00 x -120.00 y = -91.20
\n" ); document.write( "96.00 x + 120.00 y = 52.80
\n" ); document.write( "Add the two equations
\n" ); document.write( "-128.00 x = -38.40
\n" ); document.write( "/ -128.00
\n" ); document.write( "x = 0.30
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "112.00 x + 60.00 y = 45.60
\n" ); document.write( "33.60 + 60.00 y = 45.60
\n" ); document.write( " 60.00 y = 45.60 -33.60
\n" ); document.write( " 60.00 y = 12.00
\n" ); document.write( " y = 0.20
\n" ); document.write( "x= 0.30 cost of dearer ticket
\n" ); document.write( "y= 0.20 cost of cheaper ticket
\n" ); document.write( "m.ananth@hotmail.ca
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