document.write( "Question 816577: if 500 tickets were sold.
\n" ); document.write( "some at 40 cents.
\n" ); document.write( "the remainder at 25 cents. The amount of money received for tickets sold at 40 cents was $70 more than the tickets sold at 25 cents. find the amount of tickets that were sold at 40 cents each.
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Algebra.Com's Answer #491592 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Bunch of stuff to unscramble. Start by assigning variables.\r
\n" ); document.write( "\n" ); document.write( "n = how many tickets at 0.40 dollars each
\n" ); document.write( "m = how many tickets at 0.25 dollars each.\r
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\n" ); document.write( "\n" ); document.write( "Immediately see, m+n=500.\r
\n" ); document.write( "\n" ); document.write( "Amount of money for the 40 cent tickets, 0.4*n.
\n" ); document.write( "Amount of money for the 25 cent tickets, 0.25*m.
\n" ); document.write( "'
\n" ); document.write( "0.4n=70+0.25m.\r
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\n" ); document.write( "\n" ); document.write( "OKay,two equations, two unknown variables; go to it!
\n" ); document.write( "First simplify the second, money equation:
\n" ); document.write( "40n=25m+70
\n" ); document.write( "8n=5m+14
\n" ); document.write( "5m-8n=14;
\n" ); document.write( "'
\n" ); document.write( "The system to solve can be shown as: \"highlight_green%285m-8n=14%29\" and \"highlight_green%28m%2Bn=500%29\".
\n" ); document.write( "NOW go to it!
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