document.write( "Question 69080This question is from textbook Algebra 1
\n" ); document.write( ": It says to write an equation in standard form for each line. I'm having trouble figuring out this one problem: the line crosses the x-axis at x=-3 and the y-axis at y=6. I was just wondering if anyone could tell me how to write an equation for this? \n" ); document.write( "
Algebra.Com's Answer #49159 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
One approach is to write the equation first in the \"slope-intercpt\" form, then convert this to the \"standard form\".
\n" ); document.write( "First, find the slope of the line from the given information. You have two points on the: (-3, 0) and (0, 6). These are the given x- and y-intercepts, respectively.
\n" ); document.write( "From these two points you can find the slope using: \"m+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\"
\n" ); document.write( "\"m+=+%286-0%29%2F%280-%28-3%29%29\"
\n" ); document.write( "\"m+=+6%2F3\"
\n" ); document.write( "\"m+=+2\"
\n" ); document.write( "So now you can write:
\n" ); document.write( "\"y+=+2x%2Bb\" but you have been given b, the y-intercept. It's 6.
\n" ); document.write( "\"y+=+2x%2B6\" This is the equationin the slope-intercept form. You now need to convert it to the standard form: \"ax%2Bby+=+c\"
\n" ); document.write( "\"y+=+2x%2B6\" Subtract y from both sides.
\n" ); document.write( "\"0+=+2x-y%2B6\" Subtract 6 from both sides.
\n" ); document.write( "\"-6+=+2x-y\" or \"2x-y+=+-6\"
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