document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=816563>Question 816563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a triangle ABC exists then what is the length of AB if AC=10 BC=6 and the angle  ACB= 120 degrees? How do I solve this </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #491577 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=491577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if a triangle ABC exists then what is the length of AB if AC=10 BC=6 and the angle ACB= 120 degrees? How do I solve this<BR>\n" );
document.write( "----<BR>\n" );
document.write( "The side opposite <ACB is AB<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Use the Law of Cosines to fing AB:<BR>\n" );
document.write( "AB^2 = 10^2+6^2-2*10*6*cos(120)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "AB^2 = 166<BR>\n" );
document.write( "AB =  12.88<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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