document.write( "Question 816553: [ [Genny] & Jill left home at the same time. They traveled in opposite directions. Jill traveled 15 mph faster than [Genny]. After 6 hrs. they were 630 km apart. Find [Genny's] speed. ] \n" ); document.write( "

Algebra.Com's Answer #491575 by TimothyLamb(4379) $\"\"$ $\"About$

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g = genny's speed
\n" ); document.write( "j = jill's speed
\n" ); document.write( "---
\n" ); document.write( "j = g + 15
\n" ); document.write( "---
\n" ); document.write( "since they travel in exactly opposite directions, the vector math for their relative speed is trivial, and we can simplify by assuming a single traveler moving at the relative speed of the two travelers.
\n" ); document.write( "---
\n" ); document.write( "relative speed:
\n" ); document.write( "s = g + (g + 15)
\n" ); document.write( "s = 2g + 15
\n" ); document.write( "---
\n" ); document.write( "s = d / t
\n" ); document.write( "s = 630/6
\n" ); document.write( "2g + 15 = 630/6
\n" ); document.write( "2g + 15 = 105
\n" ); document.write( "2g = 105 - 15
\n" ); document.write( "2g = 90
\n" ); document.write( "---
\n" ); document.write( "g = 45 mph
\n" ); document.write( "j = 60 mph
\n" ); document.write( "---
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