document.write( "Question 816538: You invested $6000 between two accounts paying 4% and 8% annual interest. If the total interest earned for the year was $400, how much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #491570 by mananth(16946) $\"\"$ $\"About$

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Part I 4.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 8.00% per annum ------------ Amount invested = y
\n" ); document.write( " 6000
\n" ); document.write( "Interest----- 400.00
\n" ); document.write( "
\n" ); document.write( "Part I 4.00% per annum ---x
\n" ); document.write( "Part II 8.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 6000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.00% x + 8.00% y= 400
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4 x + 8 y= 40000.00 --------2
\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
\n" ); document.write( "-4 x -4 y= -24000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 4 y= 16000
\n" ); document.write( "divide by 4
\n" ); document.write( " y = 4000
\n" ); document.write( "Part I 4.00% $ 2000
\n" ); document.write( "Part II 8.00% $ 4000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "2000 --------- 4.00% ------- 80.00
\n" ); document.write( "4000 ------------- 8.00% ------- 320.00
\n" ); document.write( "Total -------------------- 400.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

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