document.write( "Question 69073: I'm having trouble with\r
\n" ); document.write( "\n" ); document.write( "\"9x%5E3-18x%5E2-4x%2B8=0\"\r
\n" ); document.write( "\n" ); document.write( "In my steps it says first to group the terms. I think that is where I may ultimately be messing up. I've worked on it for awhile. The answers I am supposed to have when the problem is finished is: +2/3, -2/3, and 2\r
\n" ); document.write( "\n" ); document.write( "This pattern throws me off and I have more of them. A step by step guide would be a life saver.\r
\n" ); document.write( "\n" ); document.write( "~Jake
\n" ); document.write( "

Algebra.Com's Answer #49157 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You can use the technique of factoring by grouping to solve this problem.
\n" ); document.write( "\"9x%5E3+-+18x%5E2+-+4x+%2B+8+=+0\" Group the terms as follows:
\n" ); document.write( "\"%289x%5E3+-+18x%5E2%29+-+%284x+-+8%29+=+0\" Notice the change in sign of the last term. Factor \"9x%5E2\" from the first group and factor \"4\" from the second group:
\n" ); document.write( "\"9x%5E2%28x+-+2%29+-+4%28x+-+2%29+=+0\" Now you can factor the common term (x - 2).
\n" ); document.write( "\"%28x+-+2%29%289x%5E2-4%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"x-2%29+=+0\" and/or \"9x%5E2-4+=+0\"
\n" ); document.write( "If \"x-2+=+0\" then \"x+=+2\"
\n" ); document.write( "If \"9x%5E2-4+=+0\" then \"9x%5E2+=+4\" and so \"x%5E2+=+4%2F9\" and \"x+=+2%2F3\" or \"x+=+-2%2F3\"
\n" ); document.write( "Solutions:
\n" ); document.write( "\"x+=+2\"
\n" ); document.write( "\"x+=+2%2F3\"
\n" ); document.write( "\"x+=+-2%2F3\"
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