document.write( "Question 69074This question is from textbook Algebra and Trigonometry: Structure and Method
\n" ); document.write( ": When Acme Airlines changed to planes that could fly 100 km/h faster than its old ones, the time of its 2800 km Dallas-Seattle flight was reduced by 30 minutes. Find the speed of the new planes. \n" ); document.write( "
Algebra.Com's Answer #49156 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x= speed of old ones\r
\n" ); document.write( "\n" ); document.write( "x+100= speed of new ones\r
\n" ); document.write( "\n" ); document.write( "distance (d)=rate(r) times time (t) or d=rt and t=d/r\r
\n" ); document.write( "\n" ); document.write( "2800/x= time it took old planes to make the trip\r
\n" ); document.write( "\n" ); document.write( "2800/(x+100)= time it takes the new planes to make the trip\r
\n" ); document.write( "\n" ); document.write( "Now we are told that the new planes make the trip 30 min (0.5 hr) faster than the old planes. So our equation to solve is:\r
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\n" ); document.write( "\n" ); document.write( "2800/x=(2800/(x+100))+0.5 multiply both sides by x(x+100)\r
\n" ); document.write( "\n" ); document.write( "2800(x+100)=2800x+0.5x(x+100) clear parens\r
\n" ); document.write( "\n" ); document.write( "2800x+280000=2800x+0.5x^2+50x subtract 2800x and also 280000 from both sides\r
\n" ); document.write( "\n" ); document.write( "2800x-2800x+280000-280000=2800x-2800x-280000+0.5x^2+50x collect like terms\r
\n" ); document.write( "\n" ); document.write( "0=0.5x^2+50x-280000 or multiply both sides by 2\r
\n" ); document.write( "\n" ); document.write( "x^2+100x-560000=0 Quadratic in standard form\r
\n" ); document.write( "\n" ); document.write( "This quadratic can be factored:\r
\n" ); document.write( "\n" ); document.write( "(x+800)(x-700)=0\r
\n" ); document.write( "\n" ); document.write( "discount negative value for speed\r
\n" ); document.write( "\n" ); document.write( "So
\n" ); document.write( "x=700 km/hr ------------------------------speed of old planes\r
\n" ); document.write( "\n" ); document.write( "x+100=800 km/hr speed of new planes\r
\n" ); document.write( "\n" ); document.write( "Ck\r
\n" ); document.write( "\n" ); document.write( "2800/x=4 hrs
\n" ); document.write( "2800/(x+100)=3.5 hrs-----30 min less ---checks\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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