document.write( "Question 816348: Marilyn drove her car from Lubbock to Houston at an average rate of 48mph and returned over icy roads averaging 28 mph. Find the time going and returning if the time returning was 5 hours more than the time going. \n" ); document.write( "

Algebra.Com's Answer #491512 by TimothyLamb(4379) $\"\"$ $\"About$

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time going: g
\n" ); document.write( "time return: r = g + 5
\n" ); document.write( "---
\n" ); document.write( "s = d / t
\n" ); document.write( "d = s * t
\n" ); document.write( "---
\n" ); document.write( "D = 48g
\n" ); document.write( "D = 28(g + 5)
\n" ); document.write( "---
\n" ); document.write( "48g = 28(g + 5)
\n" ); document.write( "48g = 28g + 140
\n" ); document.write( "20g = 140
\n" ); document.write( "---
\n" ); document.write( "g = 7 hours
\n" ); document.write( "r = 12 hours
\n" ); document.write( "---
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