document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=816327>Question 816327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use inverse trigonometric functions to find the solutions of the equation that are in the interval [0, 2&#960;).You may enter an exact answer or round your solutions to four decimal places (this is best for this problem). (Enter your 4 answers in a comma separated list.)\r<BR>\n" );
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document.write( "cos(x)(11cos(x) + 7) = 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #491494 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=491494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cos(x)(11cos(x) + 7) = 3<BR>\n" );
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document.write( "11cos^2(x) + 7cos(x) - 3 = 0<BR>\n" );
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document.write( "Use Quadratic Formula to get:<BR>\n" );
document.write( "cos(x) = [-7 + sqrt(49-4*11*-3)]/22 = 0.2933<BR>\n" );
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document.write( "arccos(0.2933) = 1.2731 <BR>\n" );
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document.write( "OR<BR>\n" );
document.write( "cos(x) = [-7 - sqrt(49-4*11*-3)]/22 = -0.9297<BR>\n" );
document.write( "arccos(-.9297) = 2.7544<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H<BR>\n" );
document.write( "================= </SPAN>\n" );
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