document.write( "Question 816249: A Farmer has a 6% solution and a 12% solution of pesticide. How much of each must the farmer mix to have 300 gallons of an 8% solution for her spray? \n" ); document.write( "

Algebra.Com's Answer #491480 by TimothyLamb(4379) $\"\"$ $\"About$

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pesticide solutions by volume:
\n" ); document.write( "s = (p / w)100
\n" ); document.write( "where
\n" ); document.write( "p = chemical volume
\n" ); document.write( "w = water volume
\n" ); document.write( "---
\n" ); document.write( "s = volume of strong solution (gal)
\n" ); document.write( "w = volume of weak solution (gal)
\n" ); document.write( "---
\n" ); document.write( "s + w = 300
\n" ); document.write( "s = 300 - w
\n" ); document.write( "12s + 6w = (8)300
\n" ); document.write( "---
\n" ); document.write( "12s + 6w = (8)300
\n" ); document.write( "12(300 - w) + 6w = (8)300
\n" ); document.write( "3600 - 12w + 6w = 2400
\n" ); document.write( "6w = 1200
\n" ); document.write( "---
\n" ); document.write( "w = 200 gal
\n" ); document.write( "s = 100 gal
\n" ); document.write( "---
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