document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=814762>Question 814762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 17 cm long. Another side of the triangle is 7 cm longer than the third side. Determine the unknown side lengths. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #491468 by </B><A HREF=/tutors/aboutme.mpl?userid=gsmani_iyer><B>gsmani_iyer(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gsmani_iyer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gsmani_iyer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=491468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">    Let one side  =  x cm.  Then,\r<BR>\n" );
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document.write( "   Second side  =  x + 7 cm.\r<BR>\n" );
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document.write( "   Hypotenuse  =  17 cm.  (Given)\r<BR>\n" );
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document.write( "   According to the Pythagoras theorem,\r<BR>\n" );
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document.write( "   <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=17%5E2+=+x%5E2+%2B+%28x%2B7%29%5E2 ALIGN=MIDDLE  ALT=\"17%5E2+=+x%5E2+%2B+%28x%2B7%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "   =  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=289+=+x%5E2+%2B+x%5E2+%2B+14x+%2B+49 ALIGN=MIDDLE  ALT=\"289+=+x%5E2+%2B+x%5E2+%2B+14x+%2B+49\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "   =  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=289+=+2x%5E2+%2B+14x+%2B+49 ALIGN=MIDDLE  ALT=\"289+=+2x%5E2+%2B+14x+%2B+49\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "   =  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B14x%2B49+=+289 ALIGN=MIDDLE  ALT=\"2x%5E2%2B14x%2B49+=+289\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "   =  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B14x+=+289-49 ALIGN=MIDDLE  ALT=\"2x%5E2%2B14x+=+289-49\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "   =  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B14x+=+240 ALIGN=MIDDLE  ALT=\"2x%5E2%2B14x+=+240\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Dividing this equation by 2, we get\r<BR>\n" );
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document.write( "   =  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B7x+=+120 ALIGN=MIDDLE  ALT=\"x%5E2%2B7x+=+120\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "   =  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B7x-120+=+0 ALIGN=MIDDLE  ALT=\"x%5E2%2B7x-120+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "   =  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B15%29%28x-8%29+=+0 ALIGN=MIDDLE  ALT=\"%28x%2B15%29%28x-8%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  So, either (x+15) or (x-8) = 0.\r<BR>\n" );
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document.write( "   So, x = -15  or x = 8.  But x cannot be equal to -15 as it is not a real No.\r<BR>\n" );
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document.write( "   So, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x+=+8%29 ALIGN=MIDDLE  ALT=\"highlight%28x+=+8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. So one side = 8 cm. and another side = 15.\r<BR>\n" );
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document.write( "   I think, it is clear to you now. All the best.  Feel free to contact me at   gsmani9@yahoo.com as I am a home tutor in India.\r<BR>\n" );
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