document.write( "Question 69055: Given the digits 3,9,5,6& 2, howmany different 5 digit numbers reater than 41,000(using each digit once) can form? \n" ); document.write( "
Algebra.Com's Answer #49145 by josmiceli(19441)\"\" \"About 
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The 1st digit can't be 2 or 3
\n" ); document.write( "So, it has to be 5,6,or 9, or 3 choices
\n" ); document.write( "One digit is used up and there are 4 choices for the next digit
\n" ); document.write( "There are 3 choices for the next
\n" ); document.write( "There are 2 choices for the next
\n" ); document.write( "And 1 choice for the last
\n" ); document.write( "multiply all the choices together to get all the possible combination
\n" ); document.write( "\"3%2A4%2A3%2A2%2A1+=+72\" possible numbers greater than 41,000 using
\n" ); document.write( "each digit only once
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