document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=816099>Question 816099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am doing something wrong but i don't know what. My equations are x-5y = 15 and 4x-3y+26 , i multiplied the first equation by -4, then got -23y = 86 . What did i do wrong? Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #491355 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=491355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x - 5y = 15<BR>\n" );
document.write( "4x - 3y = 26\r<BR>\n" );
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document.write( "-4x + 20y = -60 {multiplied first equation by -4}<BR>\n" );
document.write( "4x - 3y = 26 {second equation stays the same}<BR>\n" );
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document.write( "17y = -34 {added the two equations}<BR>\n" );
document.write( "y = -2   {divided each side by 17}\r<BR>\n" );
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document.write( "x - 5y = 15 {first equation}<BR>\n" );
document.write( "x - 5(-2) = 15 {substituted -2, for y, into first equation}<BR>\n" );
document.write( "x + 10 = 15 {multiplied}<BR>\n" );
document.write( "x = 5 {subtracted 10 from each side}\r<BR>\n" );
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document.write( "x = 5 and y = -2<BR>\n" );
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