document.write( "Question 816076: Simplify cscx- cosxcotx
\n" ); document.write( "I rewrote the problem using reciprocals and quotients to get \"1%2Fsinx-+1%2Fsecx%2Acosx%2Fsinx\". Then I multiplied the reciprocals of cosx and cotx to get \"1%2Fsinx-+1cosx%2Fsecxsinx\" I'm not sure what to do after that.
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Algebra.Com's Answer #491341 by Alan3354(69443)\"\" \"About 
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Simplify cscx- cosxcotx
\n" ); document.write( "I rewrote the problem using reciprocals and quotients to get \"1%2Fsinx-+1%2Fsecx%2Acosx%2Fsinx\". Then I multiplied the reciprocals of cosx and cotx to get \"1%2Fsinx-+1cosx%2Fsecxsinx\" I'm not sure what to do after that.
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\n" ); document.write( "cscx- cosxcotx
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\n" ); document.write( "= 1/sin - cos^2/sin
\n" ); document.write( "= (1 - cos^2)/sin
\n" ); document.write( "= sin^2/sin
\n" ); document.write( "= sin(x)
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