document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=816090>Question 816090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me factorise 3x^2 + x-2.<BR>\n" );
document.write( "Thank you in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #491335 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=491335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factor by grouping:\r<BR>\n" );
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document.write( "3x² + x - 2<BR>\n" );
document.write( "= 3x² + 3x - 2x - 2 {split x into two factors whose coefficients multiply to get -6 and add to get 1}<BR>\n" );
document.write( "= 3x(x + 1) - 2(x + 1) {factored 3x out of first two terms and -2 out of last two terms}<BR>\n" );
document.write( "= (3x - 2)(x + 1) {factored (x + 1) out of the two terms}<BR>\n" );
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