document.write( "Question 816049: The axis of symmetry of a parabola is the line x=4.
\n" ); document.write( "The x-intercepts are 10 and -2.
\n" ); document.write( "Suppose that the point (12,4) is on the graph;what other point must also be on the graph?
\n" ); document.write( "I keep getting the point (4,4) would be on the graph but it is wrong. What am I doing wrong and what point is on the graph? Thanks for any help.
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Algebra.Com's Answer #491326 by TimothyLamb(4379)\"\" \"About 
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the axis of symmetry of the parabola is the line x = 4
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\n" ); document.write( "this means that you can fold a graph of the parabola along the above line and the two halves of the graph will overlap perfectly.
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\n" ); document.write( "if the point p1 (12, 4) is on the parabola then another point p2 symmetrical to it must also be on the parabola.
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\n" ); document.write( "reflect p1 (12, 4) about the axis of symmetry x = 4
\n" ); document.write( "the other point p2 is at distance dx from the axis of symmetry:
\n" ); document.write( "dx = 12 - 4 = 8
\n" ); document.write( "but on the opposite side of the axis of symmetry:
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\n" ); document.write( "Answer:
\n" ); document.write( "the other point (p2) is:
\n" ); document.write( "x = 4 - dx
\n" ); document.write( "x = 4 - 8
\n" ); document.write( "x = -4
\n" ); document.write( "y = 4 (from the y-coordinate of p1)
\n" ); document.write( "(-4, 4)
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