document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=816017>Question 816017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! I need help in solving a system of equation. The answers were provided but I don't understand how problem was solved. The system of equation is:<BR>\n" );
document.write( "y=2x+3<BR>\n" );
document.write( "y=-x-9\r<BR>\n" );
document.write( "\n" );
document.write( "The answer is: (-4,-5)\r<BR>\n" );
document.write( "\n" );
document.write( "Thank you in advance for the help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #491306 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=491306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since both = y set them equal to each other<BR>\n" );
document.write( "\<BR>\n" );
document.write( "2x+3=-x-9<BR>\n" );
document.write( "add x<BR>\n" );
document.write( "3x+3=-9<BR>\n" );
document.write( "subtrac 3<BR>\n" );
document.write( "3x=-12<BR>\n" );
document.write( "divide by 3<BR>\n" );
document.write( "x=-4<BR>\n" );
document.write( "y=-x-9<BR>\n" );
document.write( "y=-(-4)-9<BR>\n" );
document.write( "y=-5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );