document.write( "Question 815906: x^2+y^2=12\r
\n" ); document.write( "\n" ); document.write( "xy=-3 \n" ); document.write( "

Algebra.Com's Answer #491295 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
Try $\"y=-3%2Fx\"$ and substitute into the circle equation:\r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2B%28-3%2Fx%29%5E2=12\"$
\n" ); document.write( " $\"x%5E2%2B9%2F%28x%5E2%29=12\"$
\n" ); document.write( " $\"x%5E4%2B9=12x%5E2\"$
\n" ); document.write( " $\"x%5E4-12x%5E2%2B9=0\"$ not factorable.\r
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\n" ); document.write( "\n" ); document.write( "First solve for x^2 according to solution to quadratic formula;
\n" ); document.write( " $\"x%5E2=%2812%2B-+sqrt%28144-4%2A9%29%29%2F%282%29\"$
\n" ); document.write( " $\"x%5E2=%2812%2B-+sqrt%28108%29%29%2F2\"$
\n" ); document.write( " $\"x%5E2=%2812%2B-+sqrt%284%2A9%2A3%29%29%2F2\"$
\n" ); document.write( " $\"x%5E2=6%2B-3%2Asqrt%283%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and then
\n" ); document.write( "x=-(6-3*sqrt(3)) or x=(6-3*sqrt(3)) or x=-(6+3*sqrt(3)) or x=(6+3*sqrt(3))
\n" ); document.write( "'
\n" ); document.write( "FINAL ANSWER FOR JUST x: $\"+x=-6%2B3%2Asqrt%283%29\"$ or $\"x=6-3%2Asqrt%283%29\"$ or $\"x=-6-3%2Asqrt%283%29\"$ or $\"x=6%2B3%2Asqrt%283%29\"$ \n" ); document.write( "

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