document.write( "Question 68970: I need help in solving these two math problems. Here is the first one.\r
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document.write( "Add. simplify if possible: 9u/u2-49 + u/u-7 This is adding here no division is included. That's just where it is underline top and bottom portions.\r
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document.write( "Next problem is:\r
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document.write( "Subtract. simplify if possible: a/a^2+5a+6 - 2/a^2+3a+2 There is no dividing with this one either. Just the underline top and bottom portions.\r
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document.write( "I will greatly appreciate if you can help with these two problems. \n" );
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Algebra.Com's Answer #49125 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a/a^2+5a+6 - 2/a^2+3a+2\r \n" ); document.write( "\n" ); document.write( "Fractions can only be subtracted if they have the same denominator. \n" ); document.write( "Factor each denominator to get; \n" ); document.write( "=a/[(a+3)(a+2)] - 2/[(a+1)(a+2)] \n" ); document.write( "The least common denominator (lcd) is (a+1)(a+2)(a+3) \n" ); document.write( "Rewrite each fraction with the lcd as its denominator: \n" ); document.write( "a(a+1)/lcd - 2(a+3)/lcd \n" ); document.write( "Since they have the same denominator subtract the numerators \n" ); document.write( "and write over the lcd, as follows: \n" ); document.write( "=[a^2+a-2a-6]/lcd \n" ); document.write( "=(a^2-a-6)/lcd \n" ); document.write( "Factor to get: \n" ); document.write( "=[(a-3)(a+2)]/[(a+1)(a+2)(a+3)] \n" ); document.write( "Cancel the common factor of (a+2) to get: \n" ); document.write( "=(a-3)/[(a+1)(a+3)] \n" ); document.write( "-------------------------------\r \n" ); document.write( "\n" ); document.write( "9u/u2-49 + u/u-7 \n" ); document.write( "=9u/[(u-7)(u+7)] + u/(u-7) \n" ); document.write( "The lcd is (u-7)(u+7) \n" ); document.write( "Rewrite the fractions with the lcd as their denominator: \n" ); document.write( "=[9u + u(u+7)]/lcd \n" ); document.write( "=(u^2+16u]/lcd \n" ); document.write( "=(u(u+16))/[(u-7)(u+7)] \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |