document.write( "Question 815617: solve 3sin^2(w)-17sin(w)+10=0 for all solutions where w is in radians between 0 and 2pi \n" ); document.write( "
Algebra.Com's Answer #491179 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
Note: When I first posted a solution, I had neglected to set my calculator to radian mode. So there were errors in the solution. This posting has these errors corrected.

\n" ); document.write( "\"3sin%5E2%28w%29-17sin%28w%29%2B10=0\"
\n" ); document.write( "First we factor:
\n" ); document.write( "\"%283sin%28w%29-2%29%28sin%28w%29-5%29=0\"
\n" ); document.write( "If you cannot see how the equation factored this way, then try using a temporary variable. Let q = sin(w). Then the equation becomes \"3q%5E2-17q%2B10=0\". It should not be too difficult to see that it factors into (3q-2)(q-5). Then just replace the q's.

\n" ); document.write( "Next we use the Zero Product Property:
\n" ); document.write( "3sin(w)-2 = 0 or sin(w)-5=0
\n" ); document.write( "Solving 3sin(w)-2 = 0 ...
\n" ); document.write( "3sin(w) = 2
\n" ); document.write( "sin(w) = 2/3
\n" ); document.write( "Using inverse sin we get a reference angle of (approximately) 0.73. Since the 2/3 is positive and since sin is positive in the 1st and 2nd quadrants we get a general solution of:
\n" ); document.write( "\"w+=+0.73+%2B+2pi%2An\" (for 1st quadrant angles)
\n" ); document.write( "\"w+=+pi-0.73+%2B+2pi%2An+=+2.41+%2B+2pi%2An\" (for 2nd quadrant angles)

\n" ); document.write( "Solving sin(w) - 5 - 0 ...
\n" ); document.write( "sin(w) = 5
\n" ); document.write( "But sin is never larger than 1 (or less than -1). So there is no solution for this.

\n" ); document.write( "Last we use the general solution equations to find the specific solutions in the specified interval.
\n" ); document.write( "From \"w+=+0.73+%2B+2pi%2An\"
\n" ); document.write( "if n = 0 then w = 0.73
\n" ); document.write( "if n = 1 (or larger) then w is too large for the interval
\n" ); document.write( "if n = -1 (or smaller) then w is too small for the interval
\n" ); document.write( "From \"w+=+2.41+%2B+2pi%2An\" (for 2nd quadrant angles)

\n" ); document.write( "if n = 0 then w = 2.41
\n" ); document.write( "if n = 1 (or larger) then w is too large for the interval
\n" ); document.write( "if n = -1 (or smaller) then w is too small for the interval

\n" ); document.write( "So the only solutions in the given interval are 0.73 and 2.41.
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