document.write( "Question 815717: [ Three times the least of three consecutive odd INTEGERS exceeds twice the greatest by 17. Find the three Integers. ] \n" ); document.write( "
Algebra.Com's Answer #491169 by TimothyLamb(4379)\"\" \"About 
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3i = 2k + 17
\n" ); document.write( "k = i + 4
\n" ); document.write( "j = i + 2
\n" ); document.write( "---
\n" ); document.write( "3i = 2k + 17
\n" ); document.write( "3i = 2(i + 4) + 17
\n" ); document.write( "3i = 2i + 8 + 17
\n" ); document.write( "---
\n" ); document.write( "i = 25
\n" ); document.write( "j = 27
\n" ); document.write( "k = 29
\n" ); document.write( "---
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