document.write( "Question 815697: A boat takes 2/3 as much time to travel downstream as to return. If the rate of the current is 8 kph, what is the rate of the boat in still water? \n" ); document.write( "

Algebra.Com's Answer #491162 by TimothyLamb(4379) $\"\"$ $\"About$

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s = d / t
\n" ); document.write( "t = d / s
\n" ); document.write( "---
\n" ); document.write( "w = 8 kph
\n" ); document.write( "---
\n" ); document.write( "d/(b + w) = (2/3)d/(b - w)
\n" ); document.write( "1/(b + w) = (2/3)/(b - w)
\n" ); document.write( "1/(b + w) - (2/3)/(b - w) = 0
\n" ); document.write( "(b - w)/(b + w)(b - w) - (2/3)(b + w)/(b + w)(b - w) = 0
\n" ); document.write( "( (b - w) - (2/3)(b + w) ) = 0(b + w)(b - w)
\n" ); document.write( "b - w - (2/3)b - (2/3)w = 0
\n" ); document.write( "(3/3)b - (2/3)b - (2/3)w - (3/3)w = 0
\n" ); document.write( "(1/3)b - (5/3)w = 0
\n" ); document.write( "(1/3)b - (5/3)8 = 0
\n" ); document.write( "b = (5/3)8(3/1)
\n" ); document.write( "b = (5)8
\n" ); document.write( "---
\n" ); document.write( "b = 40 kph
\n" ); document.write( "---
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