document.write( "Question 815701: The age of a father is 5 more than twice of his son's age. The age of the mother is the sum of her son's age and 1/3 of the father's age. The sum of all ages is 100. Find their ages. \n" ); document.write( "
Algebra.Com's Answer #491158 by algebrahouse.com(1659)\"\" \"About 
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x = son's age
\n" ); document.write( "2x + 5 = father's age {age of father is 5 more than twice son's}
\n" ); document.write( "x + (1/3)(2x + 5) = mother's age {age of mother is sum of son and 1/3 father}\r
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\n" ); document.write( "\n" ); document.write( "x + 2x + 5 + x + (1/3)(2x + 5) = 100 {sum of all ages is 100}
\n" ); document.write( "3[x + 2x + 5 + x + (1/3)(2x + 5) = 100] {multiplied entire equation by 3 to eliminate fraction}
\n" ); document.write( "3(x) + 3(2x) + 3(5) + 3(x) + 3[(1/3)(2x + 5)] = 3(100) {multiplied each term by 3}
\n" ); document.write( "3x + 6x + 15 + 3x + 2x + 5 = 300 {multiplied through}
\n" ); document.write( "14x + 20 = 300 {combined like terms}
\n" ); document.write( "14x = 280 {subtracted 20 from each side}
\n" ); document.write( "x = 20 {divided each side by 14}
\n" ); document.write( "2x + 5 = 45 {substituted 20, in for x, into 2x + 5}
\n" ); document.write( "x + (1/3)(2x + 5) = 35 {substituted 20 for x into mother's age}\r
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\n" ); document.write( "\n" ); document.write( "son is 20, father is 45, and mother is 35
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