document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=815661>Question 815661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangular garden is 7 feet longer than its width. the gardens perimeter is 186. find the length of the garden. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #491151 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=491151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = width<BR>\n" );
document.write( "x + 7 = length   {length is 7 more than width}\r<BR>\n" );
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document.write( "Perimeter of a rectangle = 2(width) + 2(length)\r<BR>\n" );
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document.write( "2x + 2(x + 7) = 186 {substituted width, length, and area into perimeter formula}<BR>\n" );
document.write( "2x + 2x + 14 = 186 {used distributive property}<BR>\n" );
document.write( "4x + 14 = 186 {combined like terms}<BR>\n" );
document.write( "4x = 172 {subtracted 14 from each side}<BR>\n" );
document.write( "x = 43 {divided each side by 4}<BR>\n" );
document.write( "x + 7 = 50 {substituted 43, in for x, into x + 7}\r<BR>\n" );
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document.write( "length of garden is 50 ft<BR>\n" );
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