document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=815647>Question 815647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have a 20 foot pole and want to hand Xmas lights from the top to the bottom with an angle of 15 degrees, how long does the strand need to be?  Looking for formula as well. \r<BR>\n" );
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document.write( "Thanks in advance.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #491143 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=491143\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If I have a 20 foot pole and want to hand Xmas lights from the top to the bottom with an angle of 15 degrees, how long does the strand need to be?<BR>\n" );
document.write( " Looking for formula as well.<BR>\n" );
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document.write( "Assume you mean 15 degree from the top of the pole<BR>\n" );
document.write( "This forms a right triangle so we can use the Cosine of the angle to find this<BR>\n" );
document.write( "Cosine = Side Adjacent/hypotenuse<BR>\n" );
document.write( "Angle = 15 degrees<BR>\n" );
document.write( "Side adjacent = 20' pole<BR>\n" );
document.write( "Hypotenuse = length of the strand to the ground (h)<BR>\n" );
document.write( "Cos(15) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20%2Fh ALIGN=MIDDLE  ALT=\"20%2Fh\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( ".9695 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20%2Fh ALIGN=MIDDLE  ALT=\"20%2Fh\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".9695h = 20<BR>\n" );
document.write( "h = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20%2F.9695 ALIGN=MIDDLE  ALT=\"20%2F.9695\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "h = 20.7 feet, about 20' 8.5 inches<BR>\n" );
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document.write( "Formula for angle at the top<BR>\n" );
document.write( "h = = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pole+ht%2FCos%28angle%29 ALIGN=MIDDLE  ALT=\"pole+ht%2FCos%28angle%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "For angle from the ground<BR>\n" );
document.write( "h = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pole+ht%2FSin%28angle%29 ALIGN=MIDDLE  ALT=\"pole+ht%2FSin%28angle%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Response to comment<BR>\n" );
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document.write( "The radius of the circle would be the side opposite the top angle (15 degrees)<BR>\n" );
document.write( "We could use the tangent of 15 to find that (side opposite/side adjacent)<BR>\n" );
document.write( "tan(15) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%2F20 ALIGN=MIDDLE  ALT=\"r%2F20\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "r = 20 * .268<BR>\n" );
document.write( "r = 5.36 ft or about 5'4\" the diameter would be 10 ft 8 inches </SPAN>\n" );
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