document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=815643>Question 815643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In my textbook it says to solve the System of Linear Equations using Substitution. The problem it gives for it is:\r<BR>\n" );
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document.write( "x= 8y-4 <BR>\n" );
document.write( "x+8y=6\r<BR>\n" );
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document.write( "Do you know how to work this out? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #491141 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=491141\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=8y-4\r<BR>\n" );
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document.write( "x+8y=6\r<BR>\n" );
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document.write( "In place of x substitute x from first equation\r<BR>\n" );
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document.write( "(8y-4)+8y=6\r<BR>\n" );
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document.write( "16y-4=6\r<BR>\n" );
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document.write( "+4 +4<BR>\n" );
document.write( "16y=10<BR>\n" );
document.write( "/16<BR>\n" );
document.write( "y=10/16\r<BR>\n" );
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document.write( "y=5/8\r<BR>\n" );
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document.write( "plug y in first equation<BR>\n" );
document.write( "x=8y-4<BR>\n" );
document.write( "x=8*(5/8)-4\r<BR>\n" );
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document.write( "x=1 </SPAN>\n" );
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