document.write( "Question 815593: A freight train leaves the station traveling 30km/hr. One hour later, a passanger train leaves the same station on parellel track at 60km/hr. How far from the station does the passanger train overtake the frieght train? \n" ); document.write( "
Algebra.Com's Answer #491098 by TimothyLamb(4379)\"\" \"About 
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s = d / t
\n" ); document.write( "d = s * t
\n" ); document.write( "---
\n" ); document.write( "when the passenger train (p) leaves the station, the cargo train (c) has already traveled one hour:
\n" ); document.write( "---
\n" ); document.write( "when p overtakes c, both trains have traveled the same distance from the station, but c has been traveling 1 hour longer than p.
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\n" ); document.write( "c at the overtake:
\n" ); document.write( "d = 30 / t
\n" ); document.write( "where t is the time of the overtake, measured from the time that c departed the station
\n" ); document.write( "---
\n" ); document.write( "p at the overtake:
\n" ); document.write( "d = 60 / (t + 1)
\n" ); document.write( "where t is the time of the overtake, measured from the time that c departed the station
\n" ); document.write( "---
\n" ); document.write( "c and p at the overtake:
\n" ); document.write( "d = 30/t = 60/(t + 1)
\n" ); document.write( "30(t + 1)/(t(t + 1)) = 60t/(t(t + 1))
\n" ); document.write( "60t/(t(t + 1)) - 30(t + 1)/(t(t + 1)) = 0
\n" ); document.write( "60t - 30(t + 1) = 0(t(t + 1))
\n" ); document.write( "60t - 30t - 30 = 0
\n" ); document.write( "30t = 30
\n" ); document.write( "---
\n" ); document.write( "time of the overtake:
\n" ); document.write( "t = 1 hour after c departed the station
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\n" ); document.write( "Answer:
\n" ); document.write( "d = 30 / t
\n" ); document.write( "d = 30 km/hr / 1 hr = 30 km
\n" ); document.write( "so the overtake occurs 30 km from the station
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