document.write( "Question 68989: the length of a rectangle is 4m more than the width.The area is 30m squared. Find the width and length. \n" ); document.write( "
Algebra.Com's Answer #49104 by checkley75(3666)\"\" \"About 
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L*W=30
\n" ); document.write( "L=W+4 thus
\n" ); document.write( "(W+4)W=30
\n" ); document.write( "W^2+4W=30
\n" ); document.write( "W^2+4W-30=0
\n" ); document.write( "USING THE QUADRATIC EQUATION WE GET
\n" ); document.write( "X=(-B+-SQRT[B^2-4QC])/2A
\n" ); document.write( "X=(-4+-SQRT16-4*1*-30])/2*1
\n" ); document.write( "X=(-4+-SQRT16+120])/2
\n" ); document.write( "X=(-4+-SQRT136)/2
\n" ); document.write( "X=(-4+-11.66)/2
\n" ); document.write( "X=(-4+11.66)/2
\n" ); document.write( "X=7.66/2
\n" ); document.write( "X=3.83M IS THE WIDTH.
\n" ); document.write( "THUS THE LENGTH IS
\n" ); document.write( "L*3.83=30
\n" ); document.write( "L=30/3.83
\n" ); document.write( "L=7.83M IS THE LENGTH
\n" ); document.write( "PROOF
\n" ); document.write( "3.83*7.83=30
\n" ); document.write( "30=30 \n" ); document.write( "
\n" );