document.write( "Question 815517: Average age of 30 students in a class is 10. then 1 more is took admission in that class. now the average of their age is 11. then find the age of last one?
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Algebra.Com's Answer #491032 by balthazar612(14) $\"\"$ $\"About$

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To solve this we know that,
\n" ); document.write( "Average of age= total ages of students/ total Students\r
\n" ); document.write( "\n" ); document.write( "10 = total ages of students/30\r
\n" ); document.write( "\n" ); document.write( "10*30= total ages of students\r
\n" ); document.write( "\n" ); document.write( "300= Total ages of students
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\n" ); document.write( "Now
\n" ); document.write( " When 1 student is added there will be total 11 students using above formula\r
\n" ); document.write( "\n" ); document.write( "Average of age= Total ages of students/ total ages of students\r
\n" ); document.write( "\n" ); document.write( "11 = total ages of students/ 31\r
\n" ); document.write( "\n" ); document.write( "Total ages of students= 31*11
\n" ); document.write( " = 341\r
\n" ); document.write( "\n" ); document.write( "Change in total age= 341 - 300
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\n" ); document.write( "Age of 11th student= 41
\n" ); document.write( " Answer= 41 \n" ); document.write( "

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