document.write( "Question 815177: if both r & s are integers > 1 ,also 11(s-1)=13(r-1) then the remainder when r+s is divided by 8 is ?
\n" ); document.write( "A.2
\n" ); document.write( "B.3
\n" ); document.write( "C.5
\n" ); document.write( "D.7 \n" ); document.write( "

Algebra.Com's Answer #490984 by KMST(5328) $\"\"$ $\"About$

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$\"+highlight%282%29\"$
\n" ); document.write( " $\"s-1+=13%2A%28%28r-1%29%2F11%29%3E=1\"$ is an integer,
\n" ); document.write( "and so is $\"%28r-1%29%2F11%3E=1\"$ .
\n" ); document.write( " $\"s=13%2A%28%28r-1%29%29%2F11%2B1\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"r%2Bs=13%2A%28%28r-1%29%2F11%29%2Br%2B1\"$
\n" ); document.write( " $\"r%2Bs=13%2A%28%28r-1%29%2F11%29%2B%28r-1%29%2B2\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"r%2Bs=%2813%2F11%2B1%29%2A%28r-1%29%2B2\"$
\n" ); document.write( " $\"r%2Bs=+%2824%2F11%29%2A%28r-1%29%2B2\"$
\n" ); document.write( " $\"r%2Bs=24%2A%28%28r-1%29%2F11%29%2B2+\"$
\n" ); document.write( " $\"r%2Bs=+8%2A3%2A%28%28r-1%29%2F11%29%2B2\"$
\n" ); document.write( "So $\"r%2Bs\"$ had a remainder of $\"highlight%282%29\"$ when divided by $\"8\"$ , or by $\"3\"$ , or by $\"24\"$ . \n" ); document.write( "

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