document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=815451>Question 815451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are complementary.the measure of the larger angle is 20 degrees morethan the measure of the smaller angle..give the measure of the two angles<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #490973 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=490973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = measure of smaller angle<BR>\n" );
document.write( "x + 20 = measure of larger angle {larger is 20 more than smaller}\r<BR>\n" );
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document.write( "Complementary angles add up to 90°.\r<BR>\n" );
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document.write( "x + x + 20 = 90   {added the two angles and set equal to 90}<BR>\n" );
document.write( "2x + 20 = 90 {combined like terms}<BR>\n" );
document.write( "2x = 70 {subtracted 20 from each side}<BR>\n" );
document.write( "x = 35 {divided each side by 2}<BR>\n" );
document.write( "x + 20 = 55 {substituted 35, in for x, into x + 20}\r<BR>\n" );
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document.write( "smaller angle measures 35°<BR>\n" );
document.write( "larger angle measures 55°<BR>\n" );
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