document.write( "Question 815433: a submarine traveling at 9.0 mph is descending at an angle of depression of 6 degrees. How many minutes, to the nearest tenth, does it take the submarine to reach a depth of 80 feet? \n" ); document.write( "
Algebra.Com's Answer #490964 by TimothyLamb(4379)\"\" \"About 
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we need the vertical velocity of the sub:
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\n" ); document.write( "user vector addition:
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\n" ); document.write( "the sub's descent velocity vector (d) is inclined 6 degrees from the horizontal and has magnitude 9 mph.
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\n" ); document.write( "sin A = opp/hyp
\n" ); document.write( "opp = magnitude of vertical velocity vector mag(v)
\n" ); document.write( "hyp = magnitude of descent velocity vector mag(d)
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\n" ); document.write( "sin(6 degrees) = mag(v) / mag(d)
\n" ); document.write( "sin(6 degrees) = mag(v) / 9
\n" ); document.write( "sin(6 degrees) * 9 = mag(v)
\n" ); document.write( "mag(v) = 0.9407561 mph
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\n" ); document.write( "s = d / t
\n" ); document.write( "t = d / s
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\n" ); document.write( "time to depth:
\n" ); document.write( "t = 80 feet / (0.9407561 miles/hour * 5280 feet/mile * 1/60 hour/minute)
\n" ); document.write( "t = 0.9663406 minutes
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\n" ); document.write( "Answer:
\n" ); document.write( "the sub will reach 80 feet of depth in 0.966 minutes or roughly 1.0 minute
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