document.write( "Question 68955: Please help me with Motion Problems-
\n" ); document.write( "A train starts from Grand City and travels toward Belleville 388 miles away. At the same time, a train starts from Belleville and runs at the rate of 47 miles per hour toward Grand City. They pass each other 4 hours later. Find the rate of the train from Grand City.
\n" ); document.write( "I don't know how to solve it exactly. Thank you for your time.
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Algebra.Com's Answer #49086 by ankor@dixie-net.com(22740)\"\" \"About 
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A train starts from Grand City and travels toward Belleville 388 miles away. At the same time, a train starts from Belleville and runs at the rate of 47 miles per hour toward Grand City. They pass each other 4 hours later. Find the rate of the train from Grand City.
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\n" ); document.write( "We know when they meet they will have traveled a total of 388 miles, and both will have traveled for 4 hours.
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\n" ); document.write( "Let s = speed of the train from G.C.
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\n" ); document.write( "Dist = time * speed
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\n" ); document.write( "Belleville train dist + G.C train dist = 388 mi
\n" ); document.write( " 4(47) + 4s = 388
\n" ); document.write( " 188 + 4s = 388
\n" ); document.write( "4s = 388 - 188
\n" ); document.write( "4s = 200
\n" ); document.write( "s = 200/4
\n" ); document.write( "s = 50 mph speed of train from G.C.
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\n" ); document.write( "Check 4(47) + 4(50) = 388
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