document.write( "Question 68955: Please help me with Motion Problems-
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document.write( "A train starts from Grand City and travels toward Belleville 388 miles away. At the same time, a train starts from Belleville and runs at the rate of 47 miles per hour toward Grand City. They pass each other 4 hours later. Find the rate of the train from Grand City.
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document.write( "I don't know how to solve it exactly. Thank you for your time. \n" );
document.write( "
Algebra.Com's Answer #49086 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A train starts from Grand City and travels toward Belleville 388 miles away. At the same time, a train starts from Belleville and runs at the rate of 47 miles per hour toward Grand City. They pass each other 4 hours later. Find the rate of the train from Grand City. \n" ); document.write( ": \n" ); document.write( "We know when they meet they will have traveled a total of 388 miles, and both will have traveled for 4 hours. \n" ); document.write( ": \n" ); document.write( "Let s = speed of the train from G.C. \n" ); document.write( ": \n" ); document.write( "Dist = time * speed \n" ); document.write( ": \n" ); document.write( "Belleville train dist + G.C train dist = 388 mi \n" ); document.write( " 4(47) + 4s = 388 \n" ); document.write( " 188 + 4s = 388 \n" ); document.write( "4s = 388 - 188 \n" ); document.write( "4s = 200 \n" ); document.write( "s = 200/4 \n" ); document.write( "s = 50 mph speed of train from G.C. \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check 4(47) + 4(50) = 388 \n" ); document.write( " \n" ); document.write( " |