document.write( "Question 815307: In how many ways can a group of 12 policemen group into 3 groups of 7, 3 and 2
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Algebra.Com's Answer #490845 by KMST(5328) $\"\"$ $\"About$

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There are 66 ways to chose 2 out of a group of 12 if the order in which they are chosen does not matter: $\"12%2A11%2F2=66\"$ .
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\n" ); document.write( "There are 120 ways to chose 3 from the remaining 10,
\n" ); document.write( " $\"12-2=10\"$ ,
\n" ); document.write( "if the order in which they are chosen does not matter:
\n" ); document.write( " $\"10%2A9%2A8%2F3%2F2=120\"$ .
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\n" ); document.write( "For each of the calculations above the math jargon is combinations of m elements taken from a set of n elements, calculated as $\"n%21%2F%28n-m%29%21m%21\"$ =

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\n" ); document.write( "So, there are 7920 ways to take a group of 2 and a group of 3 out of 12, leaving a group of 7 remaining:
\n" ); document.write( " $\"66%2A120=highlight%287920%29\"$ . \n" ); document.write( "

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