document.write( "Question 815249: The combined area of a square and a rectangle is 132 square centimeters. The width of the rectangle is 2 centimeters more than the length of a side of the square, and the length of the rectangle is 4 centimeters more than its width. Find the dimensions of the square and the rectangle. \n" ); document.write( "
Algebra.Com's Answer #490841 by mananth(16946)\"\" \"About 
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square side =x
\n" ); document.write( "area of square = x^2\r
\n" ); document.write( "\n" ); document.write( "width of rectangle = x+2
\n" ); document.write( "length of rectangle = x+2+4\r
\n" ); document.write( "\n" ); document.write( "area of rectangle = (x+2)(x+6)\r
\n" ); document.write( "\n" ); document.write( "(x+2)(x+6)+x^2= 132\r
\n" ); document.write( "\n" ); document.write( "x^2+8x+12+x^2=132\r
\n" ); document.write( "\n" ); document.write( "2x^2+8x+8\12-132=0\r
\n" ); document.write( "\n" ); document.write( "2x^2+8x-120=0
\n" ); document.write( "/2
\n" ); document.write( "x^2+4x-60=0\r
\n" ); document.write( "\n" ); document.write( "x^2+10x-6x-60=0\r
\n" ); document.write( "\n" ); document.write( "x(x+10)-6(x+10)=0
\n" ); document.write( "(x+10)(x-6)=0
\n" ); document.write( "x= 6\r
\n" ); document.write( "\n" ); document.write( "side of square = 6cm\r
\n" ); document.write( "\n" ); document.write( "width = 8cm
\n" ); document.write( "length =12 cm\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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