document.write( "Question 815286: How many liters of a 10% solution of acid should mixed with 60% solution of acid to obtain a 20 liters of 50% solution? \r
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document.write( "Please show me a step by step guide through because I want understand the material to pass a quiz on these types of questions. \n" );
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Algebra.Com's Answer #490831 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! 100*{amount of pure acid}/{amount of solution}={percentage concentration}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let u = how many liters of the 10% acid \n" ); document.write( "Let v = how many liters of the 60% acid \n" ); document.write( "Wanting 20 liters of acid solution, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using the percentage concentrations, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Solve the system for u and v. \n" ); document.write( " \n" ); document.write( " |