document.write( "Question 815286: How many liters of a 10% solution of acid should mixed with 60% solution of acid to obtain a 20 liters of 50% solution? \r
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Algebra.Com's Answer #490831 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
100*{amount of pure acid}/{amount of solution}={percentage concentration}\r
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\n" ); document.write( "\n" ); document.write( "Let u = how many liters of the 10% acid
\n" ); document.write( "Let v = how many liters of the 60% acid
\n" ); document.write( "Wanting 20 liters of acid solution, \"u%2Bv=20\".\r
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\n" ); document.write( "\n" ); document.write( "Using the percentage concentrations,
\n" ); document.write( "\"10u%2B60v\" is how much of the actual pure acid; this is in scaled-up form, since the percent concentrations are 100 times larger than their fractional meanings.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28%2810u%2B60v%29%2F20=50%29\" and \"highlight%28u%2Bv=20%29\";
\n" ); document.write( "Solve the system for u and v.
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